Question

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tell me fast at the spot don't tell the wrong answer....



What is the value of gamma for a
gas havin g 'n' degrees of freedom.

Answer 1

ANSWER :
_________

Gamma, atomicity, γ = Cp / Cv

By derivation, Gamma, γ = 1 + 2 / f

Where, f = Degrees of freedom for 'n' number of molecules.

Answer 2

hi mate here is your answer....



Suppose, the number of degrees of freedom in a polyatomic gas molecule = n
Internal energy of one gram mole of the gas,
U = n * (1/2)kT * N
Where k = Boltzmann constant, T = temerature of system and N = Avogadro number
Or U = n/2 RT
Now we know,

Cv =dU/dT = > Cv = d/dT (U)

= (n / 2) R

Also we have a relation,

Cp = Cv + R

= ( n / 2) R + R

= (n/ 2 + 1) R

Again, Cp /Cv = Y

= ( n / 2 + 1) R / ( n / 2) R = ( 1 + 2 / n)

Therefore, Y = ( 1 + 2/ n)