Question

(Hint: Area of a triangle - base x height|
Find the area of triangle with base 2x + 3 and height 3x - 1​

Answer 1

Answer:

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Answer 2

Question : -

• Find the area of triangle with base (2x + 3) and height (3x - 1).

Answer

Given :-

• A triangle have base (2x + 3) and height (3x - 1).

To Find :-

• Area of triangle

Formula used :-

$\boxed{\bf \:Area \: of \: triangle = \dfrac{1}{2} \times base \times height}$

Solution :-

It is given that, In triangle,

Base of triangle = 2x + 3

Height of triangle = 3x - 1

$\boxed{\bf \:Area \: of \: triangle = \dfrac{1}{2} \times base \times height}$

On Substituting the values of base and height, we get

$\bf\implies \:Area = \dfrac{1}{2} \times (2x + 3) \times (3x - 1)$

$\bf\implies \:Area = \dfrac{1}{2} ( {6x}^{2} - 2x + 9x - 3)$

$\bf\implies \:Area = \dfrac{1}{2} ( {6x}^{2} + 7x - 3) \: sq. \: units$

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