Hiw does the force of gravitation between two objects change when the distance between them is reduced to half
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F = G M1 M2 / R2
If d distance is half then
F = G M1 M2 / 1/2R^2
F = G M1 M2 / 1 /4R
So the force will be force times...
4F = G M1 M2 / R
So the force of gravitation will be 4 times of the previous force...
hope it helps u....if it did plzz mark me brainliest.....thanks...!!
If d distance is half then
F = G M1 M2 / 1/2R^2
F = G M1 M2 / 1 /4R
So the force will be force times...
4F = G M1 M2 / R
So the force of gravitation will be 4 times of the previous force...
hope it helps u....if it did plzz mark me brainliest.....thanks...!!
Answered by
0
☺ Hello mate__ ❤
◾◾here is your answer...
According to the universal law of gravitation, gravitational force (F),
F∝ 1/r^2
If distance r becomes r/2, then the gravitational force will be proportional to
F ∝ 1/ (r/2)^2 ∝ 4/r^2
Hence, if the distance is reduced to half, then the gravitational force becomes four times larger than the previous value.
I hope, this will help you.
Thank you______❤
✿┅═══❁✿ Be Brainly✿❁═══┅✿
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