Question

Hllo friends, please answer my question.
Solve 24x is less than 100 when xis a natural number and x is an integer.
Nyccc answer will be marked as brainlist.
So answer it immediately.

Answer 1

 24x < 100

=> x < 100/24

x < 25/6

i) It is evident that 1, 2, 3, and 4 are the only natural numbers less than.

Thus, when x is a natural number, the solutions of the given inequality are 1, 2, 3, and 4.

ii) The integers less than  are …–3, –2, –1, 0, 1, 2, 3, 4.

Thus, when x is an integer, the solutions of the given inequality are

…–3, –2, –1, 0, 1, 2, 3, 4.

Hence, in this case, the solution set is {…–3, –2, –1, 0, 1, 2, 3, 4}.

 

 

Hence, in this case, the solution set is {1, 2, 3, 4}.

Answer 2

Here is the solution :-

(i) Given that 24x < 100

Now we have to divide the inequality by 24 then we get x < 25/6

Now when x is a natural integer then

It is clear that the only natural number less than 25/6 are 1, 2, 3, 4.

Thus, 1, 2, 3, 4 will be the solution of the given inequality when x is a natural number.

Hence {1, 2, 3, 4} is the solution set.

(ii) Given that 24x < 100

Now we have to divide the inequality by 24 then we get x < 25/6

now when x is an integer then

It is clear that the integer number less than 25/6 are…-1, 0, 1, 2, 3, 4.

Thus, solution of 24 x < 100 are…,-1, 0, 1, 2, 3, 4, when x is an integer.

Hence {…, -1, 0, 1, 2, 3, 4} is the solution set.