Question

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♦♦A Cistern internally measuring 150 cm × 120 cm × 110 CM has 129600 cm^3 of water in it. Porous bricks are placed in water until the cistern is full to the brim. Each brick observes one - seventeenth of its own volume of water. How many bricks can be put in without overflowing the water each brick being 22.5 cm × 7.5 cm × 6.5 cm....??

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Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

$\boxed{\boxed{\red{\bf{1792}}}}$

Step-by-step explanation:

The volume of the cistern will be :-

Length × Breadth × Height

⇒ 150 cm × 120 cm × 110 cm

⇒ 18000 cm² × 110 cm

⇒ 1980000 cm³

Given that there is 129600 cm³ of water inside the cistern .

So the amount of empty space in the cistern :-

1980000 cm³ - 129600 cm³

⇒ 1850400 cm³ .

The volume of each brick is 22.5 cm × 7.5 cm × 6.5 cm

⇒ 1096.875 cm³

Let Number of bricks = n .

Volume of n bricks = 1096.875 n

Volume of water absorbed :-

⇒ 1/17 × n × 1096.875

⇒ 64.52 n

Volume of empty space = volume of all bricks - absorbed water

⇒ 1850400 cm³ = 1096.875 n - 64.52 n

⇒ 1032.35 n = 1850400 cm³

⇒ n = 1850400/1032.35

⇒ n = 1792.4153 approx .

∴ Number of bricks cannot be in decimal .

Hence number of bricks = 1792 .