Question

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Answer 1

Lets say first no. in ap is x. And common difference is z.
Acc. To 1st statement x +3z + x + 7z = 37 = 2x + 10z
Acc.to 2nd statement x + 5z + x + 11z = 46 = 2x + 16z
Now eq 2 - eq 1 == 9 = 6z therefore z = 1.5
Putting z solve any 1 equation. X = 11
Hence 1st 4 terms are 11, 12. 5, 14, 15.5

Answer 2

Heya dear.....❤❤
A/q,
Since given sum of 4th and 8th term is 37
So, a4+a8=37
=>a+3d+a+7d=37
=>2a+10d=37-----------(i)

Again, given sum of 6th and 8th 12th term is 46
So, a6+a12=46
=>a+5d+a+11d=46----------(ii)

Now, (ii)-(i),we get;
6d=9
=>d=3/2

Put d=3/2 in eq(i);
2a+10×3/2=37
a=11

Hence, we get a=11 and d=3/2

Therefore,
First four terms of the A.P. are
a,a+d,a+2d,a+3d
11,11+3/2,11+2×3/2,11+3×3/2
11,25/2,14,31/2

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