hlo everyone
maths question for u
Divide 27 into two parts such that the sum of their reciprocals is 3/20
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Let two parts be x and y so x+y=27. A2q, 1/x+1/y=3/20. After putting x+y=27 y=180/x putting y=180/x in eq x+y=27 x^2-27x+180 after solving x=15 & 12 these are two parts.
HOPE IT HELPS YOU :)
HOPE IT HELPS YOU :)
vickygupta37:
kha se copy kiya
Answered by
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Hey mate....
here's the answer...
Let the 2 parts
be x and 27-x
A.T. Q.....
1/X+1/27-X =3/20
By LCM,
27-X+X/X(27-X) =3/20.
x^2-27x+180=0
x^2-12x-15x+180=0
So ,
x=12 or 15
when x=12 ,
second part =27-12=15
when x=15 ,
second part =27-15=12
Hence two parts = 12 and 15
Hope this helps❤
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