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Calculate normality of solution containing 5g of NaOH dissolve in 250mL of aqueous solution.
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Solution:-
Moles of NaOH = 5/40 moles
=> Moles of NaOH = 1/8 Moles.
Molarity = (1/8)× 1000/250
=> Molarity = 1/2
Molarity = Normality * n factor.
Hence ,
Normality = 1/2.
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ananyadubey2013:
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Answered by
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Given :
Mass of NaOH = 5 gm
Volume of the solution (V) = 250 ml
To Find :
Normality of the solution
Solution :
Normality of a solution is the number of gram-equivalents of a solute dissolved in one litre of the solution.
Normality (N) = Mass of the solute (W) ÷ [gram-equivalent mass (E) × Volume of solution (V)]
Normality (N) =
Gram-equivalent weight of NaOH =
= 40 gm
Normality (N) =
= 0.5 N
Therefore, the normality of the given solution is found to be 0.5 N
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