Chemistry, asked by ananyadubey2013, 1 year ago

Hlo friends!☺️
Calculate normality of solution containing 5g of NaOH dissolve in 250mL of aqueous solution.
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Answers

Answered by UltimateMasTerMind
5

Solution:-

Moles of NaOH = 5/40 moles

=> Moles of NaOH = 1/8 Moles.

Molarity = (1/8)× 1000/250

=> Molarity = 1/2

Molarity = Normality * n factor.

Hence ,

Normality = 1/2.

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UltimateMasTerMind: Wello!❤
Answered by AnkitaSahni
4

Given :

Mass of NaOH = 5 gm

Volume of the solution (V) = 250 ml

To Find :

Normality of the solution

Solution :

Normality of a solution is the number of gram-equivalents of a solute dissolved in one litre of the solution.

Normality (N) = Mass of the solute (W) ÷ [gram-equivalent mass (E) × Volume of solution (V)]

Normality (N) = \frac{W}{E*V}

Gram-equivalent weight of NaOH = \frac{40}{1}

                                                        = 40 gm

Normality (N) = \frac{5*1000}{40 * 250}

                      = 0.5 N

Therefore, the normality of the given solution is found to be 0.5 N

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