Question

hlo friends,

if x,y,z are areas and v is the area of 3 adjacent sides of cubiod and v is the volume of cubiod dimensions a,b and c.Prove that v^2=xyz.



Urgent yaar please fast

Answer 1

hey panner... here is your answer... ⬇⬇


let the dimensions of cuboid are
Length=l
breadth=b
height =h
given area of three faces x,y and z
lb= x--(1)
bh=y---(2)
lh= z---(3)
multiply (1),(2) and (3)
lb×bh×lh= xyz

l^2×b^2×h^2=xyz

(lbh)^2= xyz

v^2= xyz
since volume of the cuboid=v=lbh

..I hope it help you....

Answer 2

SUPPOSE :-

THREE ADJESENT SIDEES HAVE AREA OF X,Y,Z

LET L= X

B=Y

H= Z

SO WHEN THE DIMENSIONLY WE CAN WRITE IT LIKE:-

BY MULTIPLYING EACH TERM:-

WE GET

L×W×H = V

SQUARE THE BOTH SIDES :-

(L×W×H)² = V²

SO APPLY THE ROOT ONE SIDE WE GET :-

V×W×H = V²

PLEASE BRAINLIEST THE ANSWER:-❗❗☺