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♥️Two satellites have their masses in the ratio 3:1. The radii of their circular orbits are in the ratio 1:4. What is the total mechanical energy of A and B?♥️
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Given : Two satellites A and B
Ratio of masses = 3:1 = mA ( mass A ) : mB (mass B )
Radius of circular orbit of A and B is r and 4r respectively.
rA : rB = r : 4r
We know that,
Mechanical energy,
E = - G Mm / 2r
therefore, E < M / r
= Let E A and EB be energy of satellites A and B
therefore, EA / EB = mA / mB * rB / rA = 3/1 * 4r/r
= EA/EB = 12/1
THE RATIO OF TOTAL MECHANICAL ENERGY IS 12:1
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