Question

★★Hlo guys★★ ____________________________________

✔✔✔what is the formula to calculate which day on that date⭕ like which day on this date 14/9/18 ✔✔✔

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Answer 1

The Key Value Method

This method uses codes for different months and years to speed up the calculation of the day of the week. You might even be able to memorize the codes. We'll use December 16, 2482 as an example.

Take the last 2 digits of the year. In our example, this is 82.

Divide by 4, and drop any remainder. 82 / 4 = 20, remainder 2, so we think "20."

Add the day of the month. In our example, 20 + 16 = 36.

Add the month's key value, from the following table.

JanFebMarAprMayJuneJulyAugSeptOctNovDec144025036146

The month for our example is December, with a key value of 6. 36 + 6 = 42.

If your date is in January or February of a leap year, subtract 1. We're using December, so we don't have to worry about this step.

Add the century code from the following table. (These codes are for the Gregorian calendar. The rule's slightly simpler for Julian dates.)

1700s1800s1900s2000s4206

Our example year is 2482, and the 2400s aren't in the table. Luckily, the Gregorian calendar repeats every four hundred years. All we have to do is add or subtract 400 until we have a date that is in the table. 2482 - 400 = 2082, so we look at the table for the 2000s, and get the code 6. Now we add this to our running total: 42 + 6 = 48.

Add the last two digits of the year. 48 + 82 = 130.

Divide by 7 and take the remainder. This time, 1 means Sunday, 2 means Monday, and so on. A remainder of 0 means Saturday. 130 / 7 = 18, remainder 4, so December 16, 2482 will be on the fourth day of the week-- Wednesday.

HOPE IT HELPS...

Answer 2

Heya mate✌
Here's your answer....
The Key Value Method

The Key Value method uses codes for different months and years to calculate the day of the week.
Steps:

Take the last 2 digits of the year.

Divide it by 4 and discard any remainder.

Add the day of the month to the value obtained in step 2.

Add the month’s key value, from the following table to the value obtained in step 3.

Jan 1
Feb 4
Mar 4
Apr 0
May 2
June 5
July 0
Aug 3
Sept 6
Oct 1
Nov 4
Dec 6

If the date is in January or February of a leap year, subtract 1 from step 4.

Add the year (century) code from the following table.

1700s 4
1800s 2
1900s 0
2000s 6
Suppose the year is not in the above table.  In this case all we have to do is add or subtract 400 until we have a year (century) that is in the table. Then get the code for the year from the above table and add the value to the previous step (our running total).

Add the last two digits of the year to the value we obtained in the previous step.

Divide this value by 7 and take the remainder. Get the day from the following table based on the value of the remainder.
Sun 1, Mon 2, Tue 3,Wed 4,Thurs 5,Fri 6,Sat 0
Now, we will try to implement the above method by taking two examples, one for a normal year and other for a leap year.
Let us take 19th November 2582 as an example.

Take the last 2 digits of the year. In our case, this is 82.

Divide it by 4 and discard any remainder. 82 / 4 = 20, remainder 2, so we take only 20 discarding 2 (remainder).

Add the day of the month. In our example, 20 + 19 = 39.

The month in our example is November, which has the key value of 4. Therefore, 39 + 4 = 43.

Our example year is 2582, and the 2500s aren’t in the table. In this case all we have to do is add or subtract 400 until we have a year (century) that is in the table. 2582 – 400 = 2182. 2100 is also not in the table. So we again subtract 2182-400=1782.Now we look at the table for the 1700s, and get the code 4. Now we add this to our running total: 43 + 4 = 47.

Add the last two digits of the year to the value we obtained in the previous step i.e. 47 + 82 = 129.

Divide this value by 7 and take the remainder.129/7=18, remainder is 3.
Here, the remainder is 3. So the day on 19th November 2582will be Tuesday.
Hope it helps you....!