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if two circles intersect at two points prove that their centre lies on the perpendicular bisector of the common chord...
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given:let circle c1 have centre O and circle c2 have x centre,pq is a common chord.
to prove: OX is a perpendicular bisector of pq I.e.
1.pq=rq
2.angle PRO =angle PRX=angle QRO=angle QRX=90°.
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