Question

Hlo ppl.... ⭐⭐⭐☺☺

Try this one..... ✔

30 points... Xd​

Answer 1

$\huge\bold\pink{Answer:-}$

For O2,

∆G=-nfE

E°=∆G/-nF

=-827000/-2×96500

=4.28

Min emf required to carry out electrolysis of Al2O3

=4.28/2

=2.14 V

Answer 2

For O2,

∆G=-nfE

E°=∆G/-nF

=-827000/-2×96500

=4.28

Min emf required to carry out electrolysis of Al2O3

=4.28/2

=2.14 V