Question

Hlo.. ☺

With explanation ✌

Answer 1

$\huge\mathfrak\red{HOLA \: MATE!!}$

$\huge\underline\mathbb\orange{ANSWER}$

$<b>Refer To The Attachment$

$\huge\boxed{Müśkåαπ}$

Answer 2

Hi ❤Tina❤

Yoooo❤❤❤

Q1/c + Q2/kc = E

Its in series so charge same

Q1 = Q2

Q1/c + Q1/kc = E

Q1/c. ( 1 + 1/k) = E

When removed

Q1'/c + Q2'/c = E

Q1'= Q2'

Q1'/c + Q1'/c = E

2 Q1'/c = E.......(1)

And Q1/c ( 1 + 1/k.) = E,....(2)

1÷2

2 Q1'/Q1 = 1 + 1/k

Q1' /Q1 = ( k +1)/ 2k

As Q1'= Q2'

Q1 = Q2

Q2'/Q2 = ( k+1)/2k

c) is correct

Thanks❤❤❤❤