Question

hockey ball at rest is hit by stick such that force acts on the ball for 0.15 s. If the ball is of mass 100 g covers a distance of 100 m in 2 seconds, find the magnitude of the force applied by the hockey stick​

Answer 1

Explanation:

Given:

• Initial Velocity of the ball (u) = 0
• Mass of the ball is 100 g.
• Time for which the force acts (t) = 0.15 s

To Find:

• Acceleration produced in the ball (a) = ?

Solution: Distance covered by the ball, when no frictional force is acting on it = 100 m

∴ Uniform velocity of the ball = Distance Travelled/Time taken

→ 100m/2s = 50 m/s

Now, Final velocity of the ball (v) = 50 m/s.

★ Formula: applying v = u + at ★

$\implies \: 50 = 0 + a \times 0.1 5 \\ \\ \implies \: 50 = 0 + 0.15a \\ \\ ∴ \: a \: = \frac{50}{0.15} = 333.3 \: m/\:s^{2} \\ \\ ∴ \: Force \: acting \: on \: the \: ball, F = ma \\ \\ = \frac{100}{1000} (kg) \times 333 .3 \: m/s ^{2} \\ \\ \implies \: 33.33N. \:$

Answer 2

Explanation:

Hey Mate,→ Given Question:-

→  A hockey ball at rest is hit by a stick, such that the force acts on the ball for 0.15s . If the ball is of mass 100 g and covers a distance of 100 m in 2 seconds, find the magnitude of the force applied by the hockey stick. Assume no friction is acting on the ball while rolling on the ground.

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→ To Find:-

→  The magnitude of the force applied by the hockey stick?

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→ Given :-

→ Distance Covered ⇒ 100m

→ Time Taken            ⇒  2s

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→  Law Used:-→ ∵ \frac{Distance covered}{Time Taken}TimeTakenDistancecovered                                                                                                                                     

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→ Solution:-

⇒  Disctance covered by the Ball

⇒ = 100m

⇒ Time Taken                            

⇒     =  2s

⇒ \frac{100m}{2s}2s100m  = 50 ms^-1−1

⇒ Now ,

⇒ Initial Velocity ( u ) = 0

⇒ Final  Velocity  ( v ) = 50ms^-1−1

⇒ Time                   ( t ) = 0.15s

⇒ Acceleration producted on ball ⇒ (α) = ?

⇒ v = u + αt

⇒ 50 = 0 + α × 0.15

⇒ α = \frac{50}{0.15}0.1550 = 333.3ms^-2−2

⇒ Force acting on the ball ,

⇒ F = \frac{100}{1000} (kg)1000100(kg) × 333.3ms^-2−2

⇒ = 33.33N

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→ More information:-

→ This question is about hockey ball and stick.

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