Physics, asked by kwwoheh, 1 year ago

hockey ball of 200g travelling at 10 m per struck by a hockey stick so as to return it along its original path with a velocity of 5 metre per second calculate the change of momentum occurred in the motion of the hockey Ball by the force applied by the hockey stick

Answers

Answered by rakshit087
7
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Answered by BrainlyRaaz
35

 \bf{\underline{\underline{Answer:}}}

 \bf{\therefore\:3\:kg\:m\:{s}^{-1}}

 \bf{\underline{Given:}}

 {Mass \:of\: hockey\: ball, \:m=200\:g\:=200/1000\:kg\:=\:0.2\:kg}

⟹{Initial \:velocity\: of\: hockey\: ball,\: u = 10\: m\: {s}^{-1}}

⟹ {Final \:velocity\: of\: hockey \:ball, v = - 5 m {s}^{-1}} (because direction becomes opposite)

 \bf{\underline {To\:Find:}}

⟹ {Change \:in \:momentum\: =\:?}

 \bf{\underline{\underline{Step\: by\: step \:explanation:}}}

We know that,

Momentum = Mass × Velocity

Therefore , momentum of ball before getting struck

⟹ {0.2\:×\:10\: = \:2 \:kg\: m \:{s}^{-1}}

Momentum of ball after getting struck

⟹ {0.2\:×\:-5 \:= \:- 1\:kg\: m\: {s}^{-1}}

Therefore, Change in momentum

= Momentum before getting struck - Momentum after getting struck

 ={2\:-\:(-1)}

⟹ { 2 \:+\: 1\: = \:3\: kg \:m\: {s}^{-1}}

Thus, change in momentum of ball after getting stuck is  \bf{3\:kg\:m\:{s}^{-1}}

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