Question

hockey ball of mass 200 gram travelling from west to east at 10 metre per second is struck by a hockey stick as a result the ball cat turn back and now has a speed of 5 metre per second the ball and the hockey stick cover in contact for 0.2 second. (1) Calculate the initial and final momentum of the ball (2) State the direction of momentum in each case (3) Calculate the rate of change of momentum of the ball. (4) What is the SI unit of (A) Momentum (B) rate of change of momentum? (5) Calculate the force exerted by the hockey stick on the ball and its direction.

PLEASE ANSWER ME.​

Answer 1

1) p is momentum

Taking west to east direction as positive

p = mv

Initial p = 200/1000 x 10 = 2 kgms^-1

Final p = 200/1000 x -5 = -1 kgms^-1

2) Initially, west to east
After contact with the hockey stick, east to west

3) rate of change of p =( -2 -1) /0.2 = -15 kgms^2

4) A kgms^1 or Ns
B kgms^2 or N

5) force exerted = rate of change of p = -15 N from east to west

Answer 2

Explanation:

Mass of the ball is 0.2 kg

Initial velocity is 10m/s

Final "" is 5 m/s

1.Initial momentum is 0.2×10=2 kgm/s

Final momentum is 0.2×-5= -1m/s

2. Direction of second ball will be negative.

3. Final momentum-Initial Momentum/time

= -3kgm/s

4.Kg m/s

5. We know that

v-u/t=acceleration

So

-5-10/0.2= -75 is acceleration

Now , using

Force =mass×acceleration

F=0.2×-75= -15Newton is the force and it is moving towards west which is generally considered negative and has retarded.

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