hoe many numbers are there between 100 and 1000 such that atleast one of their digits is 8
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I think 262 times........................................
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numbers between 100 and 1000 is 900
numbers which do not have one of their digits as 8= 8x9x9 = 648
900-648= 252
numbers having 8 as one of their digits =252
numbers which do not have one of their digits as 8= 8x9x9 = 648
900-648= 252
numbers having 8 as one of their digits =252
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