Question

Hoffmann elimination​

Answer 1

Answer:

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Explanation:

Hofmann elimination, also known as exhaustive methylation, is a process where a quaternary ammonium reacts to create a tertiary amine and an alkene by treatment with excess methyl iodide followed by treatment with silver oxide, water, and heat. After the first step, a quaternary ammonium iodide salt is created

Answer 2

Answer:

Hofmann elimination, also known as exhaustive methylation, is a process where a quaternary ammonium reacts to create a tertiary amine and an alkene by treatment with excess methyl iodide followed by treatment with silver oxide, water, and heat. After the first step, a quaternary ammonium iodide salt is created.