Question

Hola Brianlians !
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Subject : $\bold{Maths}$
$\bold{Perimeter \: and \: Area}$
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A Rectangular field is 112 m long and 100 m wide. Two roads, each 3 m wide are to be constructed at the centre of this field;
one is parallel to the length of the field and the other is parallel to the breadth of the field.
Find :
${:\implies}$ Area of the part of the field, not covered by the roads.
${:\implies}$ Cost of constructing the road at Rs.17 per m².
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✦️ No plagiarized stuff.
✦️ Proper explaination's needed!​​

Answer 1

Step-by-step explanation:

(i) Area of path BSTV=100×3=300 m

2

Area of path MNDP=112×3=336 m

2

∴ Total area of two paths

=(300+336)− Area of square HGFE

=636−3×3=627 m

2

∴ Area of field not covered by roads

= Total area of field − Area of two paths

=(112×100)−627=10573 m

2

(ii) Cost of constructing 1 m

2

area =Rs.17

∴ Cost of constructing the roads

=Rs.(17×627)=Rs.10659.

Answer 2

Answer:

Hola Friend,

Step-by-step explanation:

(i) Area of path BSTV=100×3=300 m^2

 Area of path MNDP=112×3=336 m^2

 ∴ Total area of two paths

=(300+336)− Area of square HGFE

=636−3×3=627 m&2

 ∴ Area of field not covered by roads

= Total area of field − Area of two paths

=(112×100)−627=10573 m^2

 (ii) Cost of constructing 1m^2  area =Rs.17

∴ Cost of constructing the roads

=Rs.(17×627)=Rs.10659.