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NOTE:-I will use D in place of B.
Angle subtended by a chord at the centre is double that of the angle subtended by chord on circumference.
Since diameter subtend 180° at centre therefore it subtend 90° at the circumference.
We can say that ∠ACD=90°
Since it given that AC=DC so the base angles are equal.
⇒∠CAD=∠CDA
In triangle ACD-
∠CAD+∠CDA+∠ACD=180°
Let ∠CAD=∠CDA=∅
therefore 2∅=90°
From this, we can conclude that-
∠CDA=∠CAD=45°
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Step-by-step explanation:
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