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Question for uh....
Solve :-
(x-1)³ + 8 = 0
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Step-by-step explanation:
If we call any cube root of unity w , so that w3=1, we can write this as
(x−1)3=−8w3
Taking cube roots,
x−1=−2w
x=1−2w
There are three w s so there are three solutions:
w3−1=0
(w−1)(w2+w+1)=0
w=1 or w=−1±i3–√2
x=1−2w so x=−1 or x=2±i3–√
Check: Obviously x=−1 works. We’ll check one of the others:
(2−i3–√−1)3+8=(1−i3–√)(1−i3–√)2+8=(1−i3–√)(−2−2i3–√)+8=−8+8✓
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