Question

➡HOLA....↩


If the zeros of the polynomial
$ax {}^{2} + bx + c = 0$
are in the ratio m:n, then find the value of
$\sqrt{m \div n} + \sqrt{n \div m}$

NO SPAMS...
FOLLOW ME

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Answer 1

THE NOTORIOUS

SOLUTION:

LET THE

ZEROES BE

"U"AND "T"

OF POLYNOMIAL

aX^2+bX+c

then

U +T= -b/a.....(3)

AND U×T = c/a......(4)

BUT IT IS GIVEN THAT

U/T = m/n

n/T = m/U = k.......(1)

Now

(√m/√n) +(√n/√m)

= (m+n)/(√mn)........(2)

now from (1)

we get

m=Uk

n=Tk

so

know we will put the values of m and n

in (2)

we get

(√m/√n) +(√n/√m)

=(m+n/√mn)

=(kT+kU)/(k√TU)

=k(T+U)/k(√TU)

=T+U/√TU

Now

from (3) and (4)

we get

T+U/√TU

= (-b/a)/√(c/a)

= -b/√ac

ANSWER: -b/√ac

SO I KILLED YOUR SPECIAL ONE.

THE NOTORIOUS

LORD CARBIN

ALWAYS KILLS WHO TRY TO TAKE HIS PLACE

Answer 2

hence proved

hope it helps