Question

hola!!

just need a help

Answer 1

Here we Have, Object distance = -5 m

and Radius of curvature = 3 m

So We Know that f = R/2

Therefore f = 1.5m

Using Mirror Formula 1/f = 1/v + 1/u

1/1.5 = 1/v – 1/5

= 1/v = 1/1.5 + 1/5

So, v = 1.15 m

So we can conclude that.. the image is at a distance 1.15 m from the mirror on the side opposite to the object.

And Now the Size of the image is = -v/u = -1.15/(-5) = 0.23

And We Can Also Say that The image is virtual, diminished and erect