Question

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the work done per unit volume to stretch the length by 1% of wire with cross sectional area of 1 mm square will be??

[Y=9×10^11]

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Answer 1

Work done per unit volume

=

$\frac{1}{2} \times stress \times strain$

WKT

$\frac{strain}{stress} = youngs \: moduus$

W

$= \frac{1}{2} y \times {strain}^{2}$

$\frac{1}{2} \times 9 \times {10}^{11} \times {( \frac{0.01l}{l} )}^{2} \\ \\ = 4.5 \times {10}^{11} \times {10}^{ - 4} \\ \\ = 45 \times {10}^{6}$

hope it helps

Answer 2

Answer in the above attachment