Question

HOLA MATES !!

In a ∆ ABC, Angle C = 65° and Angle B = 35° and bisector of Angle BAC meets BC in P , then

a ) AP > BP > CP

b ) BP > AP > CP

c ) AP < BP < CP

d ) BP < AP < CP


PLZ CHOOSE THE CORRECT ANSWER...

⏺ Full Explanation ⏺

#Be BRAINLY

Answer 1

here is your solutions indian

Answer 2

Step-by-step explanation:

Correct option is B)

In ΔACP, we have

∠ACP>∠CAP

⇒AP>CP...(i)

In ΔABP, we have

∠BAP>∠ABP⇒BP>AP...(ii)

From (i) and (ii), we have

BP>AP>CP.

I hope it will helpful for you !!!!