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In triangle ABD and ABC,
AD = AD (Common)
BD = BC (As AD bisects BC into 2 equal parts)
angle ADB = angle ADC ( Given)
=> By SAS, triangle ABD is congruent to triangle ABC
=> By CPCT, AB = AC
=> triangle ABC is an isosceles triangle
AD = AD (Common)
BD = BC (As AD bisects BC into 2 equal parts)
angle ADB = angle ADC ( Given)
=> By SAS, triangle ABD is congruent to triangle ABC
=> By CPCT, AB = AC
=> triangle ABC is an isosceles triangle
Answered by
3
BD=DC(S). angle ADB=angle ADC(A). AD=AD(common side). therefore ∆ADB is congruent to ∆ADC. AB=AC(Corresponding parts of Congruent Triangles). Hence Proved
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