Question

hola mates... ❗❗

in the attachment....
thanks for thehelp... plz explain nicely.. ✔✔✔
plz don't do on paper plz

Answer 1

In triangle ABD and ABC,

AD = AD (Common)

BD = BC (As AD bisects BC into 2 equal parts)

angle ADB = angle ADC ( Given)

=> By SAS, triangle ABD is congruent to triangle ABC

=> By CPCT, AB = AC

=> triangle ABC is an isosceles triangle

$hope \: helps$

Answer 2

BD=DC(S). angle ADB=angle ADC(A). AD=AD(common side). therefore ∆ADB is congruent to ∆ADC. AB=AC(Corresponding parts of Congruent Triangles). Hence Proved