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The dissociation reaction is
KCl → K+ + Cl−K2SO4
→ 2K+ + SO42−Moles of K+ =
No. of K+ from KCl (V1M1) + No of K+ from K2SO4(V2M2)
= 1(0.2 × 0.250) + 2(0.1 × 0.250 )
= 0.1Concentration of K+ = Total moles of K + Total number of K+ from both the solution
= 0.13
= 0.033 M ...✔
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Answer:
The answers is 0.13
= 0.033.
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