Question

Holaa!!!!
plz answer to the above 11th question with explaination.​

Answer 1

Explanation:

first find the molecular mass of Na2So2.10h20

next divide the 32.2g from molecular mass

next , multiply it with the number of oxygen present in Na2so2.10h20

then last , multiply with 16

now here im showing how to do it :-

1. molecular mass = 2×23 +32 +16×14+20 = 322g

2. dividing with 32.2 we get number of moles

32.2/322 = 1/10moles

3. no. of oxygen present =14

total moles of oxygen = 14× 1/10 =1.4moles

4. mass of oxygen present is

= 1.4×16 = 22.4 grams

Answer 2

Answer:

Explanation:

first find the molecular mass of Na2So2.10h20

next divide the 32.2g from molecular mass

next , multiply it with the number of oxygen present in Na2so2.10h20

then last , multiply with 16

now here im showing how to do it :-

1. molecular mass = 2×23 +32 +16×14+20 = 322g

2. dividing with 32.2 we get number of moles

32.2/322 = 1/10moles

3. no. of oxygen present =14

total moles of oxygen = 14× 1/10 =1.4moles

4. mass of oxygen present is

= 1.4×16 = 22.4 grams

May be it's helpful for you

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