Question

Holaaa!!!
plz answer to above 9th question with explaination.​

Answer 1

A body of mass $2kg$ moving up has potential energy $400J$ and kinetic energy 580 J at a point 'P' in its path. The maximum height reached by the body is $(g = 10 ms^{2})$

• $49 m$    

• $98 m$

• $196 m$                  

• $392 m$

Here, $m= 2kg$ and $g= 10\frac{m}{s^{2}}$

Let the maximum height reached by the body be 'H'.

On reaching it, its $P.E.=mgh$

This should be equal to the total energy at any instant.

$mgh=400J+580J=980J$

⇒$2\times10\timesh=980$

⇒$20h=980$

⇒$h=\frac{980}{20}$

⇒$49m$  

Answer 2

Answer:

hope it helps...

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