Question

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Answer 1

Solution :

★ In the first part it is given that 1 rabbit saw 9 elephants while going to the river.

→ Now,here it isn't mentioned that elephants too are going to the river. Hence,we can conclude that one animal which is going to the river is rabbit.

★ In the second part it is given that every elephant saw 3 monkeys going to the river while eating a banana.

→ Every elephant saw 3 monkeys i.e. 9 elephants saw 3 monkeys,again it isn't mentioned elephants are going,it is given monkeys are going. Hence,three other animals which are going to the river are monkeys.

★ In the third part it is given that each monkey had 1 tortoise in each hand.

→ If each monkey had 1 tortoise in each hand then 3 monkeys will have (one monkey has 2 hands) (3×2) = 6 tortoises.

Now,it was mentioned earlier Monkeys are going to the river and when tortoises are in the hands of monkeys then tortoises too will visit to the river.

Total animals going to the river are :

$\star \sf \: 1 \: rabbit \: + \: 3 \: monkeys \: + 6 \: tortoises$

$\longrightarrow \large \boxed{ \purple{ \sf \: 10 \: animals}}$

Answer 2

Answer:

Given:

1) A rabbit saw 9 Elephants while going into the river.

2) Ever elephant saw 3 monkeys going to the river while eating a banana.

3) Each money has 1 tortoise in each hand.

Find:

☆ How many animals are give to to river?

Explanation:

${\bold{\underline{\boxed{\red{\bold{Case-1}}}}}}$

☆ It is given that a rabbit saw 9 elephant when the rabbit was going into the river.

☆ That's 1 rabbit which was going into the river saw a 9 elephant.

☆ According to case-1, only a rabbit was going into the river but the Elephants were not going into the river.

${\bold{\underline{\boxed{\green{\bold{Result= 1 \: Rabbit}}}}}}$

${\bold{\underline{\boxed{\red{\bold{Case-2}}}}}}$

☆ It is given that 9 elephants saw 3 monkeys going to the river.

☆ This means, the 3 three monkeys were going into the river and this was seen by the 9 elephants.

☆ According to case-2, 3 monkeys were going into the river.

${\bold{\underline{\boxed{\green{\bold{Result = 3 \: Monkeys}}}}}}$

${\bold{\underline{\boxed{\red{\bold{Case-3 }}}}}}$

☆ It is given that each monkeys which was going into the river had 1 tortoise in each hand.

☆ This means, the three monkeys going to river carried 1 tortoise in each had.

☆ We, know that each money has 2 hands, so a single monkeys carried 2 monkeys.

⇒ $\bold{3 \: monkeys \times 2 \: hands}$

⇒ $\bold{6}$

☆ According to case-3, there are 2 tortoise in each 3 monkeys and that's 6 monkeys totally going into the river.

${\bold{\underline{\boxed{\green{\bold{ Results = 6 \: Tortoise }}}}}}$

☆ According to all the three cases there are 1 Rabbit, 3 Moneys and 6 Tortoise.

Calculations:

⇒ $\bold{1 + 3 + 6}$

⇒ ${\bold{\underline{\boxed{\red{\bold{10 \: animals }}}}}}$

Finally, there are 10 animals going in the river.