Physics, asked by Gur555555, 1 year ago

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●A Observation Deck of tall Skyscraper 370 m above the street . Determine the time Required for a penny to free fall from the deck to the street Below .

●A Bullet is moving at a speed of 367 m/s when it embeds into a lump of moist clay . The Bullet penetrates fpr a distance of 0.0621 m . Determine the acceleration of the bullet while moving into the clay ( Assume a uniform acceleration )
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Answers

Answered by coolkid82
0

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Answered by shree543
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  1. Questions involving accelerating objects, including those in free fall, can be solved using three equations

y = 1/2at2 + v0t + y0

v = v0 + at

vf2 = v02 + 2 a (y - y0)

In this case, only the first equation is needed.

Since the object is falling the final height is 0 meters, the initial height is 370 m, and the acceleration is -9.8ms-2

Since the object is dropped, the initial velocity is 0.

0 = 1/2(-9.8)t2 + 370. t = sqrt(370/4.9) = 8.69

2.The speed of bullet, u: 367m/s

The distance traveled before the

stop, S: 0.0621 m

Assume that ‘a’ is the

acceleration of bullet so the equation would be, if bullet comes to rest,

v^2 = u^2 +2aS

0 = 367^2 + 2a x 0.0621

a = -1094452.5 m/s^2

so the negative sign denotes that

the acceleration is directed opposite to the motion of bullet.

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