Physics, asked by topprharshnirala, 1 year ago

Honda Shine accelerates uniformly from rest to a speed of 7.10 m/s over a distance of
35.4 m. Determine the acceleration of the bike.

Answers

Answered by dreamking
3

Answer:

a=0.71200 m/s^2 .Hope it will help you

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Answered by Sameeksha777
28

Question :

Honda Shine accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.

Answer :

final velocity, v = 7.10 m/s

initial velocity, u = 0

Distance, s = 35.4 m

Acceleration, a = ?

Now,

v {}^{2}  = u {}^{2}  + 2 \: a \: s \\ 7.10 {}^{2}  = 0 {}^{2}   + 2 \times a \times 35.4 \\

0.712 m/s

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