Question

Horizontal range of a projectile is maximum when it is fired at an angle of a.30⁰ b.60⁰ c.45⁰ c.90⁰​

Answer 1

Answer:

option:c , 45°

R=u²sin2θ/g

dR/dθ=2u²(cos2θ)/g

at maxima,dR/dθ=0

cos2θ=0

2θ=90

θ=45°

Answer 2

Answer:

The horizontal range of a projectile is maximum when it is fired at an angle of 45°

Explanation:

The maximum horizontal range of a projectile is called as range.

The range is given by

$Range=u^{2} sin2θ/g$

∴ Range is directly proportional to sin2θ

sin value is maximum for 90°

∴ Range will be maximum when sin2θ=90°

∴θ=90/2=45°

Thus, the horizontal range of a projectile is maximum when it is fired at an angle of 45°