horizontal spring (K = 300 N/m) with a mass of 0.75 kg attached to its undergoing simple harmonic motion. Calculate the (a) period, (b) frequency and (c) angular frequency of this oscillator.
Answers
Given info : A horizontal spring (K = 300 N/m) with a mass of 0.75 kg attached to its undergoing simple harmonic motion.
To find : (a) period,
(b) frequency and
(c) angular frequency of this oscillator.
solution : here spring constant, K = 300 N/m
mass attached to it, m = 0.75 kg
using formula,
ω = √{K/m}
= √{300/0.75}
= √(400)
= 20 rad/s
therefore angular frequency of this oscillator is 20 rad/s.
now frequency, f = ω/2π
= 20/2π = 10/π = 3.185 Hz
and time period, T = 1/f = 1/(10/π) = π/10 = 0.314s
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