Question

hot iron ball of mass 0.2 kg is dropped into 0.5 kg of water at 10 degree Celsius .The resulting temperature is 30 degrees Celsius. calculate the temperature hot iron ball . specific heat capacity of iron= 336 joule per kg for degree Celsius and specific heat capacity of water= 4200 joule per kg per degree Celsius?

Answer 1

655 Celsius is the answer

Answer 2

Given:

Mass of iron ball =0.2 kg

mass of water = 0.5 kg

Initial temperature of water = 10°C

specific heat capacity of iron = 336 J/kg°C

specific heat capacity of water = 4200 J/kg°C

To Find: The initial temperature of iron ball T

Formula Used:

$Q=mc\Delta T$

m is the mass, c is the specific heat capacity and ΔT is the temperature difference.

Calculations:

heat lose by iron ball = heat gained by water

$m_ic_i(T-T_e)=m_wc_w(T_e-T_w)\\0.2\times 336\times (T-30)=0.5\times 4200 (30-10)\\67.2T-2016=42000\\T = 655^oC$

Thus, the initial temperature of iron was 655°C.

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