the population of a town increases by 10% annually. If the present population is 22000. Find its population a year ago.
Answers
let present population be p
then , p= 22,000
incease in population annually = 10% = 10/100 × p = p/10
10% of p = 1/10 × 22,000 = 2,200
population a year ago = p - 10% of p
= 22,000 - 2,200
= 19,800
ans - the population of the town was 19,800 a year ago.
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Answer:
let present population be p
then , p= 22,000
incease in population annually = 10% = 10/100 × p = p/10
10% of p = 1/10 × 22,000 = 2,200
population a year ago = p - 10% of p
= 22,000 - 2,200
= 19,800
ans - the population of the town was 19,800 a year ago.
Step-by-step explanation:
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