Question

House to office a man cycles to his office from
his house at a speed of 5 km/hour and reaches
10 minutes late. If he cydes at a speed of 6 km/hr,
he reaches 10 minutes early. What is the distance
between the office and his house?​

Answer 1

Answer:

Step-by-step explanation:

Hey mate..... Here is your answer:

Let d = the distance in km between house and office

Let t = The travel time in hrs which is on time for him

Given:

From office to house at 5 km/hr

(1) d=5×(t+10/60)

From office to house at 6 km/hr

(2) d=6×(t-10/60)

--------------------—-------------------------

(1)d=5t+5/6

(2)d=6t-1

-------------------—---------------------------

Substitute (1) into (2)

(2) 5t+5/6=6t-1

t=5/6+1

t=11/6

Plug this result back into (1) or (2)

(1) d=5×(11/6)+5/6

d=55/6+5/6

d=10

The distance between his house and office is 10 km

check:

(2) d=6t-1

(2) 10=6t-1

(2)6t=11

(2)t=11/6

OK

(1) d=5t+5/6

(1) 10=5t+5/6

(1) 5t=10-5/6

(1)5t=60/6-5/6

(1)5t=55/6

(1)t=11/6