Question

How 2+2=8 and 3+3=9 and 4+4=12

Answer 1

Answer:

according to pattern first divide by 1 then divide by 3 then divide by 5 as given.... this forms a series

$(( {2 + 2})^{2} - 2^{3}) \div 1 = 8$

$((3 + 3)^{2} - 3^{2}) \div 3 = 9$

$((4 + 4 )^{2} - 4 ^{1} )\div 5 = 12$

Hope it helps...

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