how ✓289=17 ?
I need step by step
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289 is a Prime number
it can be written as 17 × 17 (only possible way in whole numbers)
so
√289
√(17×17)
a^m × a^n = a^m+n
√(17)^2
√x can be written as x^1/2
(17^2)^1/2
(a^m)^n = a^mn
(17)^2/2
17^1
17
it can be written as 17 × 17 (only possible way in whole numbers)
so
√289
√(17×17)
a^m × a^n = a^m+n
√(17)^2
√x can be written as x^1/2
(17^2)^1/2
(a^m)^n = a^mn
(17)^2/2
17^1
17
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