How a value for Km can be obtained from the vo vs S graph when vo = 1/2 Vmax?
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Next, you will obtain the rate of enzyme activity as 1/Vo = Km/Vmax (1/[S]) + 1/Vmax, where Vo is the initial rate, Km is the dissociation constant between the substrate and the enzyme, Vmax is the maximum rate, and S is the concentration of the substrate.
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how a value for km can be obtained from the vo vs s graph when vo =1/2vmax
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