How an odd shape body weighing 7.5 kg and occupy 0.01 m^3 volume will be completely submerged fluid having specific gravity?
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Answered by
8
Density of liquid = m/v
= 3000/4
= 750kg/m3
Density of liquid/density of water = 750/1000
= 0.75
specific gravity.
Hope it will help you
Answered by
1
The specific gravity of the submerged fluid is 0.75.
Weight of the body =7.5kg (GIven)
Volume occupied by the body = 0.01m³ (GIven)
The density of a liquid equals the total mass of the liquid divided by its volume. Thus,
D = m/v
= 3000/4
= 750
Thus, the density of liquid is 75kg
Specific gravity of the fluid will be calculated as-
Density of the liquid/ Density of the water
= 750/1000
= 0.75
Thus, the specific gravity of the fluid is 0.75.
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