Question

How are 0.50 mol $Na_{2}CO_{3}$ and 0.50 M $Na_{2}CO_{3}$ different?

Answer 1

We know that the molar mass of sodium carbonate is 106  

Molar mass of $Na_{2}CO_{3}$ = (2 × 23) + 12.00 + (3× 16) = 106 g mol$^{-1}$

1 mole of  $Na_{2}CO_{3}$  = 106 g

 

0.5 mol of $Na_{2}CO_{3}$  = (106/1mole) x 0.5 mol  $Na_{2}CO_{3}$

= 53 g  $Na_{2}CO_{3}$

⇒ 0.50 M of  $Na_{2}CO_{3}$  = 0.50 mol/L  $Na_{2}CO_{3}$

 

Hence, 0.50 mol of  $Na_{2}CO_{3}$  is present in 1 L of water or 53 g of  $Na_{2}CO_{3}$  is present in 1 L of water.