How can 3 resistors of resistances 2 ohms, 3 ohms and 6 ohms be connected to give a total resistance of (i) 4 ohms? (ii) 1 ohm?
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Explanation:
There are three resistors of resistances 2 Ω, 3 Ω, and 6 Ω respectively. ...
This equivalent resistor of resistance 2 Ω is connected to a 2 Ω resistor in series.
Therefore, the equivalent resistance of the circuit = 2 Ω + 2 Ω = 4 Ω Hence the total resistance of the circuit is 4 Ω
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