How can be solve but using formula
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Answers
Answer:
So if they are growing at a rate of 10%
It means in 1 year, increase = (10/100) x 200
= 20
That Means 20 Mosquitoes increase per year.
(i) No. of Mosquitoes after 3 years = 200 + (3 x 20) = 200+60 = 260
(ii) No. of Mosquitoes after 10 years = 200 + (10 x 20) = 200+200 = 400
(iii) No. of Mosquitoes after n years = 200 + (n x 20) = 20n + 200
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Answer:
i) 3 years = 240
ii) 10 year = 380
iii) n years = 180 + 20n
Step by step explanation :
10 % of 200 = 20
i) for 3 years,
a= 200
n= 3
d= 20
a(for 3 years) = a + (n-1)d
= 200 + (3-1)20
= 200 + 40
= 240
ii) Similarly for 10 years,
a(for 10 years) = 200 + (9)20
= 200 + 180
= 380
iii) Similarly for n years,
a(for n years)= 200 + ( n - 1) 20
= 200 + 20n - 20
= 180 + 20n
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