Question

how can i factorize x^4-22x^2-75 / como factorizo x^4-22x^2-75

Answer 1

Answer:

let X^2 =t

then given equation became

t^2-22t -75

t^2 -25t+3t -75

t(t-25) +3(t-25)

(t-25) (t+3)

then possible value of t are 25 and -3

therefore

X^2 =25 and X^2=-3

X^2=-3 is being rejected as X^2 cannot be negative or less than 0

Hence possible value of X are 5,-5