how can i solve the empirical formula of an oxide of nitrogen containing 30.4 per cent of nitrogen ?
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Answer:
Nitrogen=30.4%
Oxygen=69.6%
Determine the chemical formula of the oxide
No.of moles of nitrogen=
14
30.4
=2.17
No.of moles of oxygen=
16
69.6
=4.35
A ratio of moles of nitrogen to oxygen is 2:4=1:2
Hence the formula of the oxide is NO
2
Molar mass of the oxide=14+(2×16)=46
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