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since, log√a + √b = log√ab
a² + b² = 7ab
a² + 2ab + b² = 7ab + 2ab
(a + b )² = 9ab
divide equation by 9 ,
(a+b)²/9 = ab
( a+b/3 ) = ab
a+b/3 = √ab
therefore , log a+b/3 = log √ab = log√a + log√b
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