How can three resistances of 2Ω ,3Ω and 6Ωbe connected so
as to give a total resistance of 1Ω ? Justify your answer.
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Here, 6 Ω and 3 Ω resistors are connected in parallel. This equivalent resistor of resistance 2 Ω is connected to a 2 Ω resistor in series. Hence the total resistance of the circuit is 4 Ω. ... Therefore, the total resistance of the circuit is 1 Ω.
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Answer:
all the resistors should be connected in parallel
Explanation:
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