How can three resistors of 3ohm be connected to give 9 ohm and 1 ohm
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In series
R1+R2+R3
3+3+3=9 OHM
In parallel
1/R1+1/R2+1/R3
1/3+1/3+1/3=3 OHM
Awiseman:
in parallel the answer is 1 ohm
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i am sure that this is correct hope this will help you. please also mark as brainest answer
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